64z^2=100

Solution for 64z^2=100 equation:

64z^2=100

We move all terms to the left:

64z^2-(100)=0

a = 64; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·64·(-100)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*64}=\frac{-160}{128}
=-1+1/4
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*64}=\frac{160}{128}
=1+1/4
$